(x^2+4x-4)(2x-5)=

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Solution for (x^2+4x-4)(2x-5)= equation: 


Simplifying
(x2 + 4x + -4)(2x + -5) = 0

Reorder the terms:
(-4 + 4x + x2)(2x + -5) = 0

Reorder the terms:
(-4 + 4x + x2)(-5 + 2x) = 0

Multiply (-4 + 4x + x2) * (-5 + 2x)
(-4(-5 + 2x) + 4x * (-5 + 2x) + x2(-5 + 2x)) = 0
((-5 * -4 + 2x * -4) + 4x * (-5 + 2x) + x2(-5 + 2x)) = 0
((20 + -8x) + 4x * (-5 + 2x) + x2(-5 + 2x)) = 0
(20 + -8x + (-5 * 4x + 2x * 4x) + x2(-5 + 2x)) = 0
(20 + -8x + (-20x + 8x2) + x2(-5 + 2x)) = 0
(20 + -8x + -20x + 8x2 + (-5 * x2 + 2x * x2)) = 0
(20 + -8x + -20x + 8x2 + (-5x2 + 2x3)) = 0

Combine like terms: -8x + -20x = -28x
(20 + -28x + 8x2 + -5x2 + 2x3) = 0

Combine like terms: 8x2 + -5x2 = 3x2
(20 + -28x + 3x2 + 2x3) = 0

Solving
20 + -28x + 3x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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